Then the force could well be F=kqvB from the z-guidance

QUESTION: A level of electrical energy is set of the volts x amps x time. A level of mechanized time is laid out (or is) by the force x point and that compatible energizing time. When electricity is changed into mechanical, a power should be produced by implementing current and you can most recent (amps). So is this a paradox? Electricity was functionally force x date when you’re mechanized energy is push x range.

ANSWER: step one V=step 1 J/C and you will 1 A=step 1 C/s, therefore 1 volt ·amp·second=step 1 Joules=force·point. Zero discrepancy, no contradiction. A different way to consider this is that current minutes current was fuel and you can strength is actually W=J/s.

Follow-up Question: I entirely keep in mind that 1 amplifier try step 1 coulomb per 2nd. I am not sure in which step one volt is equivalent to step one joule each coulomb is inspired by otherwise why that is right.

ANSWER: Brand new electric job Age is defined to get the newest force F considered by a charge Q split up by Q. The fresh new electric potential V is described as Age moments range d more that it serves. V=Ed=Fd/Q=[J/C]

QUESTION: magnetized force to the charges q moving that have acceleration v =qV x B easily observe that it charges out of a vehicle swinging that have exact same speed and direction while the regarding q than simply it velocity once the observed because of the me will be 0 therefore the push would be 0.i am not in a position to appreciate this issues at the same time force non no as well as almost every other go out it is 0

ANSWER: The issue is the digital and magnetized fields in a single figure away from site won’t be the same as with some other swinging frame. (This might be special relativity.) For you personally you initially begin by a magnetic career and you can zero digital industry. Imagine that the latest magnetic occupation is in the y-guidance, B=jB, E=0, and the speed out-of q is within the x-assistance, v=iv. Regarding the swinging body type the newest areas could well be B’=j?B and you will E’=k?vB, where ?=1/ v(1-(v/c) 2 ). Observe that E’=v x B’; therefore the push, since found in brand new swinging physique is F’=qE’=qv x B’=k?qvB, as you would expect. Note, however, you to definitely F’ ?F , it disagree by a very important factor out of ?; the reason being push is considered to get not Lorentz invariant and is also not really a good amounts into the relativity.

QUESTION: Easily use some magnetized taverns, clipped him or her really well so as that I can put them together with her so you’re able to form a globe, with the same rod pointing outward, Atheist dating and also the almost every other pole directing inwards, do I have a charismatic monopole target?

ANSWER: Think of your bars as dipoles of positive and negative magnetic charges (monopoles) separated by a distance d. The magnitude of the magnetic field B of a monopole is inversely proportional to the square of the distance r from the charge, B=kq/r 2 where k is some constant. In the drawing above the field at point p is B=B_-q+B_+q=kq[(1/(r-d) 2 -(1/r+d) 2 ]=4kqrd/[(r+d) 2 (r-d) 2 ]. The field does not look like a monopole because it falls off like 1/r 3 , not 1/r 2 .

Now, look at the profession when r>>d: B?4kqd/r step three

QUESTION: Guess You will find a fee +q and there is a place P , Imagine We place an excellent conductor amongst the charge +q and you may P . Since there are totally free electrons on it , Negative electrons flow with the +q and you may equivalent confident charges within the conductor near P , The newest conductor possess charges shipments for example a good dipole. Therefore if I want to determine E job during the P . I am able to explore superposition concept to get E on P due so you’re able to +q and you can Age due to dipole. But Gauss’s rules says you to dipole cannot contribute anything to E industry at P. Are you willing to describe myself ‘intuitively’ (Perhaps not from inside the equations) why the fresh new dipole cannot contribute almost anything to the field at P ?